Schnelles Finden des letzten gesäten Wortes?

[root_s2yse8vt]

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Nehmen wir an, ich traue keiner Seed-Phrase, die von irgendjemandem außer mir erstellt wurde, und ich möchte meine eigene BIP39-Seed-Phrase mit 24 Wörtern erstellen. Ich verwende die Würfelwurfmethode, um die ersten 23 Wörter zu randomisieren. Das 24. Wort kann nicht einfach irgendein Wort sein, da es die Prüfsumme ist. Gibt es eine schnelle Möglichkeit, das letzte Wort zu ermitteln? Ein ausführbares Programm oder eine HTML-Datei, die auf einem Laptop ausgeführt werden kann, wäre ideal, da ich weiß, dass es ein gewisses Risiko birgt, dass ich meine ersten 23 Wörter in ein Gerät eintippe.

Ich weiß, dass dies nichts mit Ledger zu tun hat, aber es ist eine allgemeine Frage über Krypto-Wallet, so dass ich hoffe, es ist erlaubt.

—-update—-

Ich habe ein Python-Skript gefunden, das meine Anforderungen erfüllt. Sehr einfaches Skript und für meine Nicht-Programmierer-Augen, scheint nicht bösartig.

https://github.com/veebch/Bip39-Dice

[xamarian]

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You basically need a SHA256 checksum, the rest can easily done by hand or script.
– Transfer your 23 words into their 11-bit values and put them together -> 253 bits
– add 3 bits of your choosing (8 possibilities) and do the SHA256 checksum
– the 3 bits plus the first byte of the checksum represent the 11 bits of your 24th word

[R-cryptos]

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That last word is actually calculated. First three bits are part of your private key. The last 5 bits are a checksum. You can do it easily on a linux machine, btc sessions did a video on the process: https://youtube.com/watch?v=LxTkLwpV1Po&feature=share9

Or search ‘permissionless bitcoin wallets btc sessions’ if you do not trust hyperlinks on reddit.

[brianddk]

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1. https://pypi.org/project/mnemonic/
2. https://github.com/iancoleman/bip39

Either will work, but most don’t have the technical chops to run either of those air-gapped. You may have to run 256 attempts to hit a valid seed. Be warned.

[stay_safe_and_calm]

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How to calculate the last 8 bits of word 24 by using the SHA256 checksum of your first 23 words + 3 bit of the last word is described here: For this method described below you do not need any tools which you have to trust.

[https://bitcoinmagazine.com/culture/diy-bitcoin-private-key-project](https://bitcoinmagazine.com/culture/diy-bitcoin-private-key-project)

But many hardware wallets suggest you possible words for the 24 word if you typed in the first 23 words. For example Coldcard which I have but also other wallets as bitbox will do this for you.

[Legitimate-Ad-6385]

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I may be wrong about this but I don’t think every single combo of 24 words is associated with a private key. Your method may take a very long time to actually generate a private key using 24 random words from the list

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[Lyuseefur]

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Several projects that can help with missing 22-24 words. Beyond that impossibility

[Autor]

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